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5k^2-10k-240=0
a = 5; b = -10; c = -240;
Δ = b2-4ac
Δ = -102-4·5·(-240)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-70}{2*5}=\frac{-60}{10} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+70}{2*5}=\frac{80}{10} =8 $
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